最长公共前缀
编写一个函数来查找字符串数组中的最长公共前缀。
如果不存在公共前缀,返回空字符串
""
。
示例 1:
输入:strs = ["flower","flow","flight"]
输出:"fl"
示例 2:
输入:strs = ["dog","racecar","car"]
输出:""
解释:输入不存在公共前缀。
提示:
1 <= strs.length <= 200
0 <= strs[i].length <= 200
strs[i]
仅由小写英文字母组成
暴力枚举
TypeScript
function longestCommonPrefix(strs: string[]): string {
if (!strs.length) return "";
if (strs.length === 1) return strs[0];
for (let i = 0; i < strs[0].length; i++) {
for (let j = 0; j < strs.length; j++) {
if (strs[0][i] !== strs[j][i]) {
return strs[0].slice(0, i);
}
}
}
return strs[0];
};
二分查找法
TypeScript
function longestCommonPrefix(strs: string[]): string {
if (strs.length === 0) {
return "";
}
let minLen = Number.MAX_SAFE_INTEGER;
for (const str of strs) {
minLen = Math.min(minLen, str.length);
}
let low = 0;
let high = minLen;
while (low < high) {
const mid = Math.floor((low + high + 1) / 2);
if (isCommonPrefix(strs, mid)) {
low = mid;
} else {
high = mid - 1;
}
}
return strs[0].substring(0, low);
}
function isCommonPrefix(strs: string[], len: number): boolean {
const prefix = strs[0].substring(0, len);
for (let i = 1; i < strs.length; i++) {
if (!strs[i].startsWith(prefix)) {
return false;
}
}
return true;
}
字典
TypeScript
class TrieNode {
children: Map<string, TrieNode> = new Map();
isEndOfWord: boolean = false;
}
class Trie {
root: TrieNode = new TrieNode();
insert(word: string): void {
let node = this.root;
for (let i = 0; i < word.length; i++) {
const c = word.charAt(i);
if (!node.children.has(c)) {
node.children.set(c, new TrieNode());
}
node = node.children.get(c)!;
}
node.isEndOfWord = true;
}
searchPrefix(prefix: string): TrieNode | null {
let node = this.root;
for (let i = 0; i < prefix.length; i++) {
const c = prefix.charAt(i);
if (!node.children.has(c)) {
return null;
}
node = node.children.get(c)!;
}
return node;
}
}
function longestCommonPrefix(strs: string[]): string {
if (strs.length === 0) {
return "";
}
const trie = new Trie();
for (const str of strs) {
trie.insert(str);
}
let node = trie.root;
let prefix = "";
while (node.children.size === 1 && !node.isEndOfWord) {
const nextChar = node.children.keys().next().value;
prefix += nextChar;
node = node.children.get(nextChar)!;
}
return prefix;
}